How do I solve this log equation?
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2 (5^ (x+1) ) = 1 + 3/(5^x) That's 2 times (5 to the power of (x+1) = 1 plus (3 divided by (5 to the power x) I need the answer to be in the form of a + log b where the log is in base 5 and a and b are integers. The problem I have with this equation is the addition (of numbers not of logs). How can I put the x's to one side of the equation and take logs if there is addition?
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Answer:
cwjakesteel at Yahoo! Answers Visit the source
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