How do I solve this? Factoring and Trinomials?
-
-
Answer:
C = 500x + 60000 There is not enough information here to give a numerical value for either c or x. You already have c in terms of x, in your original equation. To get x in terms of c: C = 500x + 60000 500x+60000=C Subtract 60,000 500x=c-60,000 Divide 500 x=c/500 + 120 Factoring trinomials? I presume you mean something of the form ax^2 + bx + c If a=1, i.e. of the form x^2+bx+c, it's much easier. x^2+bx+c = (x+p)(x+q) What two numbers (i. e., p and q) multiplied together give you c and added together give you b? If you know your basic multiplication and addition tables, this is easy! If the sign in front of both b and c is positive, the signs in front of p and q are both positive. If the sign in front of c is positive and in front of b is negative, both signs are negative. If the sign in front of c is negative the signs in front of p and q are different. If b is positive, the larger number of p and q is positive. If b is negative, the larger number of p and q is negative. pq=c; p+q=b. If you know the values of b and c, you can find the values of p and q. Just make sure you keep the signs for b and c. Sounds horrible. It will come with practice! If a is not equal to 1, things get more complicated. I think this will do for now!
Wolf at Yahoo! Answers Visit the source
Other answers
you cant find it unless you know the value of x and factoring trinomials has 2 ways decomposition and logical reasoning i would suggest googling them as i dont want to explain
C = 500x + 60000 There is not enough information here to give a numerical value for either c or x. You already have c in terms of x, in your original equation. To get x in terms of c: C = 500x + 60000 500x+60000=C Subtract 60,000 500x=c-60,000 Divide 500 x=c/500 + 120 Factoring trinomials? I presume you mean something of the form ax^2 + bx + c If a=1, i.e. of the form x^2+bx+c, it's much easier. x^2+bx+c = (x+p)(x+q) What two numbers (i. e., p and q) multiplied together give you c and added together give you b? If you know your basic multiplication and addition tables, this is easy! If the sign in front of both b and c is positive, the signs in front of p and q are both positive. If the sign in front of c is positive and in front of b is negative, both signs are negative. If the sign in front of c is negative the signs in front of p and q are different. If b is positive, the larger number of p and q is positive. If b is negative, the larger number of p and q is negative. pq=c; p+q=b. If you know the values of b and c, you can find the values of p and q. Just make sure you keep the signs for b and c. Sounds horrible. It will come with practice! If a is not equal to 1, things get more complicated. I think this will do for now!
John Sollows
you cant find it unless you know the value of x and factoring trinomials has 2 ways decomposition and logical reasoning i would suggest googling them as i dont want to explain
Related Q & A:
- How do I solve the problem of downloading word document attached to my email?Best solution by support.google.com
- How do I solve a DNS error?Best solution by Yahoo! Answers
- How do you solve this chemistry problem? Need HELP?Best solution by Yahoo! Answers
- How do I solve the coin problem?Best solution by Quora
- How we can solve this html problem?Best solution by wiki.answers.com
Just Added Q & A:
- How many active mobile subscribers are there in China?Best solution by Quora
- How to find the right vacation?Best solution by bookit.com
- How To Make Your Own Primer?Best solution by thekrazycouponlady.com
- How do you get the domain & range?Best solution by ChaCha
- How do you open pop up blockers?Best solution by Yahoo! Answers
For every problem there is a solution! Proved by Solucija.
-
Got an issue and looking for advice?
-
Ask Solucija to search every corner of the Web for help.
-
Get workable solutions and helpful tips in a moment.
Just ask Solucija about an issue you face and immediately get a list of ready solutions, answers and tips from other Internet users. We always provide the most suitable and complete answer to your question at the top, along with a few good alternatives below.