I need help solving this chem problem. find the molecular mass of CH4 methane?
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what is the percent difference the molecular mass of natural gas and the molecular mass of methane. I was given 0.188 g of natural gas, 757.8 mm for barometric pressure, 350 K for temperature and the density of the gas is 0.627g/L. I know the formula for finding the Molecular mass of natural gas is dRT/P but Im lost
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Answer:
MW of Methane (periodic table) CH4, 12+4 = 16 g/mol MW of natural gas PV=nRT ---> convert 757.8 mm Bar to Atm. = 0.7578 atm .7578 * V = 350 * R * n ---> rearrange to n/V= .7578/(350*R) = molarity* .627 g/L divided by molarity* = *a number* (g/mol) FYI natural gas is methane.... % difference equation is found at http://www.engineersedge.com/math/percentages-calculations.htm
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MW of Methane (periodic table) CH4, 12+4 = 16 g/mol MW of natural gas PV=nRT ---> convert 757.8 mm Bar to Atm. = 0.7578 atm .7578 * V = 350 * R * n ---> rearrange to n/V= .7578/(350*R) = molarity* .627 g/L divided by molarity* = *a number* (g/mol) FYI natural gas is methane.... % difference equation is found at http://www.engineersedge.com/math/percentages-calculations.htm
Rob
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