How hard is it to find a tenured position?

Particle's velocity is always twice its position?Find the acceleration and position function of the particle?

  • Answer:

    dx/dt = 2x x = x₀e^(2t), .. where x₀ = x(t=0) v = dx/dt = 2x₀e^(2t) a = dv/dt = 4x₀e^(2t)

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dx/dt = 2x x = x₀e^(2t), .. where x₀ = x(t=0) v = dx/dt = 2x₀e^(2t) a = dv/dt = 4x₀e^(2t)

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