How to find the equation of the lines that pass through a point and are perpendicular to the line?
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Answer:
Use the point-slope equation: y-y1=m(x-x1) A line perpendicular to another line has a slope that is multiplied by (-1) of the first. So in this case, the first line has a slope of -1/2, so the perpendicular line has a slope of 2/1 or just 2. y-0=2(x-1) y=2x-2 <== Answer
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Other answers
Use the point-slope equation: y-y1=m(x-x1) A line perpendicular to another line has a slope that is multiplied by (-1) of the first. So in this case, the first line has a slope of -1/2, so the perpendicular line has a slope of 2/1 or just 2. y-0=2(x-1) y=2x-2 <== Answer
ParadigM
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