Given triangle ABC, A = 120, a = 8, b = 3; determine B to the nearest whole degree. Do not use a decimal point?
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Answer:
Apply sines law: a / sin A = b / sin B 8 / sin 120º = 3 / sin B sin B = (3/8) * sin 120º
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Other answers
Apply sines law: a / sin A = b / sin B 8 / sin 120º = 3 / sin B sin B = (3/8) * sin 120º
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