Calculate the mass of ammonium chloride produced and the amount of ammonium chloride which reacts?
-
-
Answer:
NaOH + NH4Cl --> NaCl + H2O + NH3 0.025L x 2M = 0.05moles NaOH 0.05moles NaOH requires 0.05moles NH4Cl = 2.67g NH4Cl reacts 0.05moles NH3 produced x 22.4L/mole = 1.12L
Caroline Miller at Yahoo! Answers Visit the source
Other answers
NaOH + NH4Cl --> NaCl + H2O + NH3 0.025L x 2M = 0.05moles NaOH 0.05moles NaOH requires 0.05moles NH4Cl = 2.67g NH4Cl reacts 0.05moles NH3 produced x 22.4L/mole = 1.12L
Caroline Miller
(a) 1.7 gm (b)1.12 litre
Imran
im guessing NH3 is ammonia and HCl is hydrogen chloride. so the ratio is 1:1 because 2 g of each. so i guess you would try to find the mass of each element. so find the mass of NH3 times 2 + HCl times 2. = your answer of mass produced.
Lauren
(a) 1.7 gm (b)1.12 litre
Related Q & A:
- How can PCR or mass spectrometer be used to detect an unknown new bacteria to which no human has exposed?Best solution by Yahoo! Answers
- Which (chemical) is produced by fermentation?Best solution by acs.org
- How to calculate the molar mass?Best solution by Yahoo! Answers
- From which type of tax,the Govt. of India earns a maximum amount of revenue?Best solution by Yahoo! Answers
- How do you calculate the molar mass of a compound?Best solution by eHow old
Just Added Q & A:
- How many active mobile subscribers are there in China?Best solution by Quora
- How to find the right vacation?Best solution by bookit.com
- How To Make Your Own Primer?Best solution by thekrazycouponlady.com
- How do you get the domain & range?Best solution by ChaCha
- How do you open pop up blockers?Best solution by Yahoo! Answers
For every problem there is a solution! Proved by Solucija.
-
Got an issue and looking for advice?
-
Ask Solucija to search every corner of the Web for help.
-
Get workable solutions and helpful tips in a moment.
Just ask Solucija about an issue you face and immediately get a list of ready solutions, answers and tips from other Internet users. We always provide the most suitable and complete answer to your question at the top, along with a few good alternatives below.