A shell explodes into two fragments, one fragment 25 times heavier than the other. If any gas from the explosi?
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1. the momentum change of the heavier fragment is 25 times as great as the momentum change of the lighter fragment. 2. the kinetic energy change of the heavier fragment is 25 times as great as the kinetic energy change of the lighter fragment. 3. the momentum change of the lighter fragment is 25 times as great as the momentum change of the heavier fragment. 4.the kinetic energy change of the lighter fragment is 25 times as great as the kinetic energy change of the heavier fragment. 5.the momentum change of the lighter fragment is exactly the same as the momentum change of the heavier fragment.
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Answer:
Since initial momentum is zero, final total momentum must be zero too, so m1 v1 + m2 v2 = 0 and since m2 = 25 m1, then v1 = - 25 v2 The momentum changes of the two fragments are respectively m1 v1 = - 25 m1 v2 m2 v2 = 25 m1 v2 which shows that the two momentum changes are the same in modulus but with opposite sign. The kinetic energy changes are: 1/2 m1 v1² = 25² m1 v2² / 2 1/2 m2 v2² = 25 m1 v2² / 2 which shows that the kinetic energy change of the lighter fragment is 25 times as great as the kinetic energy change of the heavier fragment.
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Since initial momentum is zero, final total momentum must be zero too, so m1 v1 + m2 v2 = 0 and since m2 = 25 m1, then v1 = - 25 v2 The momentum changes of the two fragments are respectively m1 v1 = - 25 m1 v2 m2 v2 = 25 m1 v2 which shows that the two momentum changes are the same in modulus but with opposite sign. The kinetic energy changes are: 1/2 m1 v1² = 25² m1 v2² / 2 1/2 m2 v2² = 25 m1 v2² / 2 which shows that the kinetic energy change of the lighter fragment is 25 times as great as the kinetic energy change of the heavier fragment.
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