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How do you find the derivative of a function?

I can't find how to get the derivative of this function! cos^2 (x) + sin^2 (x)?

  • Answer:

    y = cos^2 (x) + sin^2 (x) y = 1 dy/dx = 0 answer//

Engr. Ronald at Yahoo! Answers Visit the source

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For all values of x cos^2(x)+sin^2(x)=1 so the derivative is zero. You can find the derivative of cos^2(x), it is 2cosxX-sinx = -2sinxcosx and the derivative of sin^2(x) is 2sinxcosx and adding gives zero as before.

Elizabeth M

For all values of x cos^2(x)+sin^2(x)=1 so the derivative is zero. You can find the derivative of cos^2(x), it is 2cosxX-sinx = -2sinxcosx and the derivative of sin^2(x) is 2sinxcosx and adding gives zero as before.

Elizabeth M

sin^2 (x) + cos^2 (x) = 1 so the derivative would be 0.

≈ nohglf

sin^2 (x) + cos^2 (x) = 1 so the derivative would be 0.

≈ nohglf

y = cos^2 (x) + sin^2 (x) y = 1 dy/dx = 0 answer//

Engr. Ronald

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