Why isn't this quicksort working?
-
We were given code for quicksort as part of a larger project and are supposed to modify it to have a random pivot value instead of using the last element, as given in the initial implementation. However, my attempt at randomizing the pivot isn't working (the original worked just fine); when I sort the sequence and output it, it gives me only some of the values in the sequence in order with extra repetitions and leaves some out. What am I doing wrong? template <typename Object, typename Comp> class QuickSort { // QuickSort class protected: Comp comp; void quickSortStep(VectorSequence<Object>& S, int leftBound, int rightBound); // recursive utility public: QuickSort() : comp() {} void sort(VectorSequence<Object>& S); // main entry point }; template <typename Object, typename Comp> void QuickSort<Object, Comp>:: // recursive portion quickSortStep(VectorSequence<Object>& S, int leftBound, int rightBound) { if (leftBound >= rightBound) return; // 0 or 1 elements /***Pivot choice 1: last element. Commented out when not in use*****************/ // Object pivot = S.atRank(rightBound).element(); // select last as pivot /*************************************... /***Pivot choice 2: random element in sequence. Commented out when not used.**************/ srand(time(NULL)); Object pivot = S.atRank(leftBound + rand()%(rightBound-leftBound + 1)).element(); /*************************************... int leftIndex = leftBound; // will scan rightward int rightIndex = rightBound - 1; // will scan leftward while (leftIndex <= rightIndex) { while ((leftIndex <= rightIndex) && // scan right to larger comp(S.atRank(leftIndex).element(), pivot) <= 0) leftIndex++; while ((rightIndex >= leftIndex) && // scan left to smaller comp(S.atRank(rightIndex).element(), pivot) >= 0) rightIndex--; if (leftIndex < rightIndex) // both elements found S.swapElements(S.atRank(leftIndex), S.atRank(rightIndex)); } // until indices cross // Shift right the right half of the sequence // instead of swapping the last element with the middle element int i = rightBound; while (i > leftIndex) { S.replaceAtRank(i, S.atRank(i-1).element()); i--; } // pivot at leftIndex S.replaceAtRank(leftIndex, pivot); // Swap the last element with the middle element //S.swapElements(S.atRank(leftIndex), S.atRank(rightBound)); quickSortStep(S, leftBound, leftIndex-1); // recur on both sides quickSortStep(S, leftIndex+1, rightBound); } template <typename Object, typename Comp> void QuickSort<Object, Comp>:: sort(VectorSequence<Object>& S) { // main entry point if (S.size() <= 1) return; // 0 or 1 elements quickSortStep(S, 0, S.size()-1); // call sort utility }
-
Answer:
I guess some thing you are missing. Usually three possibilities arises: All n-1 elements are less than pivot All the n-1 elements are more than pivot Some of the n-1 are more and some or less. In the first two cases quicksort has to be called only once. Where as in the third case quicksort has to be recusrively called on two portions. I am dont know you have taken care of this or not
Charges R at Yahoo! Answers Visit the source
Other answers
I guess some thing you are missing. Usually three possibilities arises: All n-1 elements are less than pivot All the n-1 elements are more than pivot Some of the n-1 are more and some or less. In the first two cases quicksort has to be called only once. Where as in the third case quicksort has to be recusrively called on two portions. I am dont know you have taken care of this or not
James Bond
Related Q & A:
- Why isn't Yahoo chat working?Best solution by Yahoo! Answers
- Why isn't my limewire working?Best solution by Yahoo! Answers
- Why isn't rundll32.exe working?Best solution by howtogeek.com
- Why isn't my mic working?Best solution by Yahoo! Answers
- Why isn't my browser working?Best solution by Yahoo! Answers
Just Added Q & A:
- How many active mobile subscribers are there in China?Best solution by Quora
- How to find the right vacation?Best solution by bookit.com
- How To Make Your Own Primer?Best solution by thekrazycouponlady.com
- How do you get the domain & range?Best solution by ChaCha
- How do you open pop up blockers?Best solution by Yahoo! Answers
For every problem there is a solution! Proved by Solucija.
-
Got an issue and looking for advice?
-
Ask Solucija to search every corner of the Web for help.
-
Get workable solutions and helpful tips in a moment.
Just ask Solucija about an issue you face and immediately get a list of ready solutions, answers and tips from other Internet users. We always provide the most suitable and complete answer to your question at the top, along with a few good alternatives below.