Two negatively charged bodies, each charged with -5.0*10^-5 C, are 0.20 m from each other.?
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1. Two negatively charged bodies, each charged with -5.0*10^-5 C, are 0.20 m from each other. What force acts on each particle? 2. How far apart are two electrons if they excerpt a force of repulsion of 1.0N on each other? 3. Two identical positive charges exert a repulsive force of 6.4 x 10-9 N when separated by a distance of 3.8 x 10-10 m. Calculate the charge of each.
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Answer:
Use F = kQ1Q2/R² where k=9*10^9 if charges are of equal signs then force is repulsive otherwise attractive.
Jonathan at Yahoo! Answers Visit the source
Other answers
Use F = kQ1Q2/R² where k=9*10^9 if charges are of equal signs then force is repulsive otherwise attractive.
Ravi
In all cases you apply F=(kq1q2)/(r^2). q1 and q2 are the charges and r is the distance b/w them. value of k is approx 9x10^9 F/m. 1.in the formula put in values for q1(=)q2, and r and you get 6.25x10^-8 N. 2. Put q1 and q2 as charge on an electron(1.6x10^-19 C) and F as given and find r. answer is 6.25x10^18 m 3. Same drill just find charge. answer is 3.04x10^-14 C. Oh yeah my answers may be very wrong so just work them out and check. but the method is fine i think.
Madhusudan R
Idk :) hope this helps :)
Alicia ARMANI
In all cases you apply F=(kq1q2)/(r^2). q1 and q2 are the charges and r is the distance b/w them. value of k is approx 9x10^9 F/m. 1.in the formula put in values for q1(=)q2, and r and you get 6.25x10^-8 N. 2. Put q1 and q2 as charge on an electron(1.6x10^-19 C) and F as given and find r. answer is 6.25x10^18 m 3. Same drill just find charge. answer is 3.04x10^-14 C. Oh yeah my answers may be very wrong so just work them out and check. but the method is fine i think.
Madhusudan R
Idk :) hope this helps :)
Alicia ARMANI
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