If your titration solution is 0.403 M in NaOH, and the endpoint occurs at 13.00 mL of titrant, how many mmol..?
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Answer:
I do not really follow what you are asking here, but: Mol NaOH in 13.00mL of 0.403M solution = 13/1000*0.403 = 0.00524 mol NaOH There are 5.24mmol of NaOH
Sophia S at Yahoo! Answers Visit the source
Other answers
I do not really follow what you are asking here, but: Mol NaOH in 13.00mL of 0.403M solution = 13/1000*0.403 = 0.00524 mol NaOH There are 5.24mmol of NaOH
Trevor H
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