How effective are skids?

A 2300-kg truck skids 18 m. If 43 kJ of work are done by friction, find the coefficient of friction?

  • Answer:

    Work of friction= Force of friction • distance W = FΔr [1] Force of friction = coefficent of kinetic friction • normal force F = μN N = mg, so: F = μmg [2] Plug [2] into [1]. W = μmgΔr W = 43 kJ m = 2300-kg Δr = 18 m g = 9.80 m/s•s Plug and chug, and solve for your coefficient μ. Make sure you convert 43 kJ to 43 000 J first.

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Other answers

Work of friction= Force of friction • distance W = FΔr [1] Force of friction = coefficent of kinetic friction • normal force F = μN N = mg, so: F = μmg [2] Plug [2] into [1]. W = μmgΔr W = 43 kJ m = 2300-kg Δr = 18 m g = 9.80 m/s•s Plug and chug, and solve for your coefficient μ. Make sure you convert 43 kJ to 43 000 J first.

Daryl

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