What Is Vector Trap?

Let Vector B= 4.70 m at 60°. Let Vector C have the same magnitude as Vector A and a direction angle greater th?

• Answer:

  Let's say the direction of vector A is angle θ. A · B = ||A|| ||B|| cos(θ - 60°) = 31.8 [1] B · C = ||B|| ||A|| cos(θ - 60° + 25°) = 38.1 [2] [1] / [2]: cos(θ - 60°) / cos(θ - 35°) = 31.8 / 38.1 38.1cos(θ - 60°) = 31.8cos(θ - 35°) 38.1(cosθcos60° + sinθsin60°) = 31.8(cosθcos35° + sinθsin35°) cosθ(38.1cos60° - 31.8cos35°) = sinθ(31.8sin35° - 38.1sin60°) (38.1cos60° - 31.8cos35°) / (31.8sin35° - 38.1sin60°) = tanθ θ = 25.4° (direction of vector A; the other solution of 205.4° would make the scalar products negative) Substitute θ into [1] to solve for ||A||. ||A|| (4.70) cos(25.4° - 60°) = 31.8 ||A|| = 8.22 m