What is the empirical formula of the unknown compound?
-
-
Answer:
mass of C in 17.7 g of CO2 = 17.7 x MM C / MM CO3 = 17.7 x 12 / 44 = 4.827 g mass of H = 7.26 x 2 / 18 = 0.8067 g mass of H + C = 5.6339 g so mass of O in the sample 7.8 - 5.6339 = 2.1661 g moles of C = 4.827 / 12 = 0.4023 moles moles of H = .8067 / 1.008 = 0.8003 moles moles of O = 2.1661 / 16 = 0.1354 moles molar ratio of C : H : O = 0.4023: 0.8003:: 0.1354 divide by the smallest number we get 3:6:1 empirical formula is C3H6O
vettebabe at Yahoo! Answers Visit the source
Other answers
mass of C in 17.7 g of CO2 = 17.7 x MM C / MM CO3 = 17.7 x 12 / 44 = 4.827 g mass of H = 7.26 x 2 / 18 = 0.8067 g mass of H + C = 5.6339 g so mass of O in the sample 7.8 - 5.6339 = 2.1661 g moles of C = 4.827 / 12 = 0.4023 moles moles of H = .8067 / 1.008 = 0.8003 moles moles of O = 2.1661 / 16 = 0.1354 moles molar ratio of C : H : O = 0.4023: 0.8003:: 0.1354 divide by the smallest number we get 3:6:1 empirical formula is C3H6O
bob_the_...
Related Q & A:
- How to find the empirical formula?Best solution by Yahoo! Answers
- What are some endangered animals that are unknown to most people?Best solution by Yahoo! Answers
- What is the algebraic formula?Best solution by freemathhelp.com
- What is the molecular formula of quinine?Best solution by Yahoo! Answers
- What is the empirical formula of the hydrocarbon?Best solution by wiki.answers.com
Just Added Q & A:
- How many active mobile subscribers are there in China?Best solution by Quora
- How to find the right vacation?Best solution by bookit.com
- How To Make Your Own Primer?Best solution by thekrazycouponlady.com
- How do you get the domain & range?Best solution by ChaCha
- How do you open pop up blockers?Best solution by Yahoo! Answers
For every problem there is a solution! Proved by Solucija.
-
Got an issue and looking for advice?
-
Ask Solucija to search every corner of the Web for help.
-
Get workable solutions and helpful tips in a moment.
Just ask Solucija about an issue you face and immediately get a list of ready solutions, answers and tips from other Internet users. We always provide the most suitable and complete answer to your question at the top, along with a few good alternatives below.