PLEASE HELP WITH STOICHIOMETRY MASS PROBLEMS?
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Okay I am in the 8th grade and I am having trouble on my science (stoichiometry) please please help me I am so lost! 1. 2AgNO3 + BaCl2 ---> 2AgCl + Ba(NO3)2 How many grams of silver chloride are produced from 5.0 grams of silver nitrate reacting with an excess of barium chloride? 2. How much barium chloride is necessary to react with the silver nitrate in the problem above? (problem 1) Please help me I am so lost and I will very greatly appreciate any helpful answers!
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Answer:
First you need to find the moler mass of each of the elements and make sure if there is 2Ag multiply the moler mass of Ag by 2 same goes for each of the other elments..you can look up a moler mass chart online and it will tell u the molar mass of each elements Then for the first equation, add up how much of the moler mass of 2AgNO3 and BaCl2 it took to create what ever the moler mass of silver nitrate...then create a propotion goodluck anymore questions email me! [email protected]
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Other answers
First you need to find the moler mass of each of the elements and make sure if there is 2Ag multiply the moler mass of Ag by 2 same goes for each of the other elments..you can look up a moler mass chart online and it will tell u the molar mass of each elements Then for the first equation, add up how much of the moler mass of 2AgNO3 and BaCl2 it took to create what ever the moler mass of silver nitrate...then create a propotion goodluck anymore questions email me! [email protected]
ellen
For #1: Convert grams of silver nitrate to moles by dividing by its molecular weight. With the equation that you have, two moles of silver nitrate produce two moles of silver chloride, so just take the moles of silver nitrate you computed and multiply by the molecular weight of silver chloride. For #2: From the equation, it takes one mole of barium chloride per two moles of silver nitrate, so divide the number of moles of silver nitrate by two, and then multiply that value by the molecular weight of barium chloride.
Mark S, JPAA
For #1: Convert grams of silver nitrate to moles by dividing by its molecular weight. With the equation that you have, two moles of silver nitrate produce two moles of silver chloride, so just take the moles of silver nitrate you computed and multiply by the molecular weight of silver chloride. For #2: From the equation, it takes one mole of barium chloride per two moles of silver nitrate, so divide the number of moles of silver nitrate by two, and then multiply that value by the molecular weight of barium chloride.
Mark S, JPAA
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