What is copper nitrate + sodium iodide yields to copper iodide + iodine + sodium nitrate in equation?
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Answer:
2Cu(NO3)2 + 4NaI ----> 2CuI + I2 + 4NaNO3 If you have trouble with this, think that theoretically it makes CuI2, copper(II) iodide which is unstable and breaks down to form CuI, copper(I) iodide and iodine 2CuI2 --> 2CuI + I2 so you must make start with 2Cu(NO3)2
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Other answers
2Cu(NO3)2 + 4NaI ----> 2CuI + I2 + 4NaNO3 If you have trouble with this, think that theoretically it makes CuI2, copper(II) iodide which is unstable and breaks down to form CuI, copper(I) iodide and iodine 2CuI2 --> 2CuI + I2 so you must make start with 2Cu(NO3)2
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