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How are vector spaces viewed as universal algebras?

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    For the vector x in V there exists a vector (-x) called the negative of x such that (-x) + x = x + (-x) = 0.Then v + x = w + x v + x +(-x)= w + x+(-x) v+0= w+0 The zero vector 0is a vector in V, such that for all u in V we have 0+u=u+0=u.Then v+0= w+0 implies that v=w

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For the vector x in V there exists a vector (-x) called the negative of x such that (-x) + x = x + (-x) = 0.Then v + x = w + x v + x +(-x)= w + x+(-x) v+0= w+0 The zero vector 0is a vector in V, such that for all u in V we have 0+u=u+0=u.Then v+0= w+0 implies that v=w

Since x + (-x) = 0 v + x + (-x) = v = w = w + x + (-x)

thirteenthgrave

Since x + (-x) = 0 v + x + (-x) = v = w = w + x + (-x)

thirteenthgrave

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