A.How many grams of nh3 can be produced from 3.09 mol of n2 b.. how many grams of nh3 can be produced from 3.09 mol of n2 c. how many grams are needed of h2 are needed to produce 13.04g of nh3?
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Answer:
Preliminary calculations: NH3 contains one atom of nitrogen and three atoms of hydrogen in each mole. Therefore, the molecular weight of NH3 is 14.007 + 3(1.008) = 17.031. The fraction of nitrogen by weight in this molecule is 14.007/17.031 = 0.82244. a. 3.09 moles of nitrogen has a mass of 3.09 X 2.00 X 14.007 = 86.56 grams. From this, 86.56/0.82244 = 105 grams of NH3 can be produced. b. is the same question as a. and therefore has the same answer! c. Since the molecule contains only two elements, its fraction by weight of hydrogen is 1 - 0.82244 = 0.17756. The amount of hydrogen needed is therefore 0.17756(13.04) = 2.31 grams, to the justified number of significant digits.
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