How many molecules of NaCl are produced if 58 grams of HCl reacts with excess NaOH?
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Answer:
The reaction is: HCl + NaOH ---> NaCl + H2O, there is 58/36.45=1.59 mol of HCl used = mol of NaCl produced = 92.9 g of NaCl.
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Other answers
The reaction is: HCl + NaOH ---> NaCl + H2O, there is 58/36.45=1.59 mol of HCl used = mol of NaCl produced = 92.9 g of NaCl.
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