How much ammonia is produced when 6.96 moles of hydrogen gas react with an excess of nitrogen gas?
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Answer:
For this question, you can just ignore the excess. 4H2 + N2 â 2NH4 4 mol H2 + 1 mol N2 â 2 mol NH4 6.96/4 = 1.74 6.96 mol H2 + 1.74 mol N2 â 3.48 mol NH4 3.48 mol NH4 3.48 mol NH4 x 18.05 g NH4/ 1 mol NH4 = 62.81 g NH4 Some nitrogen gas N2 will also be produced because there was an excess.
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