How do u calculate the molality of a solution prepared by dissolving 25.0grams of NaF in 800 grams of water? +Holy cow!!!+
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Answer:
90 grams gluclose / 800 grams water = 0.5 mol glucose / .8 L water = .625 M solution.
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Other answers
90 grams gluclose / 800 grams water = 0.5 mol glucose / .8 L water = .625 M solution.
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