how to directly convert char to numbers?

How to convert a 2d char array to a 2d int array?

• char puzzle[i][j]; int i,j,count=0; char value[81]; for( i = 0; i < 9; i++){ for( j = 0; j < 9; j++){ cin >> value[count]; puzzle[i][j] = value[count]; count++; }} This what I have so far. I tried using atoi but I needed a char * str. The input is: ..4545.. (numbers and periods) I'm trying to convert the char puzzle[i][j] to an int puzzle[i][j]. The char array currently holds "..4545.." and I want to covert it so it holds just integers "00454500".

• Answer:

  Engaging psychic debugger... Performing Jedi mind tricks... This is the code you want: int puzzle[9][9]; // changed type int i,j,count=0; char value[81]; for( i = 0; i < 9; i++ ) { for( j = 0; j < 9; j++ ) { cin >> value[count]; puzzle[i][j] = value[count] - '0'; // convert from ASCII digit to integer count++; } }