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how to get the size of an image without downloading it?

Get image size wihout downloading it in Python

  • How can I get dimensions of image without actually downloading it? Is it even possible? I have a list of urls of images and I want to assign width and size to it. I know there is a way of doing it locally (http://stackoverflow.com/questions/1507084/how-to-check-dimensions-of-all-images-in-a-directory-using-python), but I don't want to download all the images. Edit: Following ed. suggestions, I edited the code. I came up with http://codepad.org/dC1RSwxi. Not sure weather it downloads whole file or just a part (as I wanted).

  • Answer:

    If you're willing to download the first 24 bytes of each file, then http://code.google.com/p/bfg-pages/source/browse/trunk/pages/getimageinfo.py (mentioned in johnteslade's answer to the question you mention) will work out the dimensions. That's probably the least downloading necessary to do the job you want. import urllib2 start = urllib2.urlopen(image_url).read(24) Edit (1): In the case of jpeg files it seems to need more bytes. You could edit the function so that instead of reading a StringIO.StringIO(data) it instead reads the file handle from urlopen. Then it will read exactly as much of the image as it needs to find out the width and height.

grotos at Stack Overflow Visit the source

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This is based on ed's answer above, mixed with other things I found on the web. I ran into the same issue as grotos with .read(24). Download getimageinfo.py from https://code.google.com/p/bfg-pages/source/browse/trunk/pages/getimageinfo.py and download ReSeekFile.py from http://www.dalkescientific.com/writings/diary/archive/2005/05/18/updated_reseekfile.html. import urllib2 imgdata = urllib2.urlopen(href) image_type,width,height = getimageinfo.getImageInfo(imgdata) Modify getimageinfo as such... import ReseekFile def getImageInfo(datastream): datastream = ReseekFile.ReseekFile(datastream) data = str(datastream.read(30)) #Skipping to jpeg # handle JPEGs elif (size >= 2) and data.startswith('\377\330'): content_type = 'image/jpeg' datastream.seek(0) datastream.read(2) b = datastream.read(1) try: while (b and ord(b) != 0xDA): while (ord(b) != 0xFF): b = datastream.read(1) while (ord(b) == 0xFF): b = datastream.read(1) if (ord(b) >= 0xC0 and ord(b) <= 0xC3): datastream.read(3) h, w = struct.unpack(">HH", datastream.read(4)) break else: datastream.read(int(struct.unpack(">H", datastream.read(2))[0])-2) b = datastream.read(1) width = int(w) height = int(h) except struct.error: pass except ValueError: pass

jeffrg

It's not possible to do it directly, but there's a workaround for that. If the files are present on the server, then implement the API endpoint that takes image name as an argument and returns the size. But if the files are on the different server, you've got no other way but to download the files.

plaes

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