C++ Convert char array to int representation

I'm not sure what exactly you mean, but characters are stored in memory as their "representation", so you don't need to convert anything. If you still want to, you have to be more specific. EDIT: You can Try to read byte by byte shifting the result 8 bits left and oring it with the next byte. Try to use mpz_inp_raw

You can use a tree similar to http://en.wikipedia.org/wiki/Huffman_coding compression algorithm, and then represent the path in the tree as numbers. You'll have to keep the dictionary somewhere, but you can just create a constant dictionary that covers the whole ASCII table, since the compression is not the goal here.

There is no conversion needed. You can just use pointers. Example: char array[4 * NUMBER]; int *pointer; Keep in mind that the "length" of pointer is NUMBER.

As mentioned, character strings are already ranges of bytes (and hence easily rendered as decimal numbers) to start with. Number your bytes from 000 to 255 and string them together and you've got a decimal number, for whatever that is worth. It would help if you explained exactly why you would want to be using decimal numbers, specifically, as hex would be easier. If you care about compression of the underlying arrays forming these numbers for Unicode Strings, you might be interested in: http://en.wikipedia.org/wiki/Standard_Compression_Scheme_for_Unicode If you want some benefits of compression but still want fast random-access reads and writes within a "packed" number, you might find my "NSTATE" library to be interesting: http://hostilefork.com/nstate/ For instance, if you just wanted a representation that only acommodated 26 english letters...you could store "test" in: NstateArray<26> myString (4); You could read and write the letters without going through a compression or decompression process, in a smaller range of numbers than a conventional string. Works with any radix.

Assuming you want to store the integers(I'm reading as ascii codes) in a string. This will add the leading zeros you will need to get it back into original string. character is a byte with a max value of 255 so it will need three digits in numeric form. It can be done without STL fairly easily too. But why not use tools you have? #include <iostream> #include <sstream> using namespace std; char array[] = "test"; int main() { stringstream out; string s=array; out.fill('0'); out.width(3); for (int i = 0; i < s.size(); ++i) { out << (int)s[i]; } cout << s << " -> " << out.str(); return 0; } output: test -> 116101115116 Added: change line to out << (int)s[i] << ","; output test -> 116,101,115,116,