How Can I Convert Struct?

How to convert c struct definitions to c++

• iov[0] = (struct iovec) { .iov_base = &req, .iov_len = sizeof(req) }; I'm trying to convert a bit of code from the ss network utility to c++, and the above and similar keeps giving these errors: main.cpp|83|error: expected primary- expression before ‘struct’ main.cpp|83|error: expected ‘)’ before ‘struct’

• Answer:

  C++ doesn't support that syntax. Try this: iovec iov[2]; iov[0].iov_base = &req; iov[0].iov_len = sizeof req; /* ... */ Or maybe: iovec iov[] = { { &req, sizeof req }, /* ... */ } What you were trying is a C99 feature called "compound literals". Also, the .iov_base thing is called a "designated initializer".