Uwant totestcreatedWeb site so you have 250 people access it. Of the peps accessing the site 75 of them exp. computer crashes. Construct a 95 percent confidence interval for the proportion of crashes?
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Answer:
Estimated p = 75 / 250 = 0.3 Variance of proportion = p*(1-p)/n = 0.3(0.7)/250 =0.00084 S.D. of p is sqrt[0.00084] = 0.029 Confidence interval: phat-zval*sd = 0.3 - (1.96)(0.028983) phat-zval*sd = 0.3 + (1.96)(0.028983) Confidence interval is ( 0.2432 , 0.3568 )
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