How do I display this XML document?

How do I resolve BeanDefinitionStoreException: IOException parsing XML document from ServletContext resource [/WEB-INF/dispatcher-servlet.xml] in Java Spring MVC web project?

• Error Stack trace:     SEVERE: StandardWrapper.Throwable     org.springframework.beans.factory.BeanDefinitionStoreException: IOException parsing XML document from ServletContext resource [/WEB-INF/dispatcher-servlet.xml]; nested exception is http://java.io.FileNotFoundException: Could not open ServletContext resource [/WEB-INF/dispatcher-servlet.xml]   dispatcher-servlet.xml <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="Index of /schema/beans" xmlns:xsi="Page on w3.org" xmlns:context="Index of /schema/context" xmlns:p="Page on springframework.org" xmlns:mvc="Index of /schema/mvc" xmlns:beans="Index of /beans" xsi:schemaLocation="Page on springframework.org Page on springframework.org Page on springframework.org Page on springframework.org"> <mvc:annotation-driven/> <context:component-scan base-package="com.exam.www" /> <!-- Factory bean that creates the Mongo instance --> <bean id="mongo" class="org.springframework.data.mongodb.core.MongoFactoryBean"> <property name="host" value="localhost" /> </bean> <!-- MongoTemplate for connecting and quering the documents in the database --> <bean id="mongoTemplate" class="org.springframework.data.mongodb.core.MongoTemplate"> <constructor-arg name="mongo" ref="mongo" /> <constructor-arg name="databaseName" value="Results" /> </bean> <!-- Use this post processor to translate any MongoExceptions thrown in @Repository annotated classes --> <bean class="org.springframework.dao.annotation.PersistenceExceptionTranslationPostProcessor" /> <bean id="jspViewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver" p:prefix="/WEB-INF/jsp" p:suffix=".jsp" /> <!-- <bean class="org.springframework.web.servlet.view.tiles2.TilesViewResolver"/> <bean class= "org.springframework.web.servlet.view.tiles2.TilesConfigurer"> --> <!-- <property name="definitions"> <list> <value>/WEB-INF/views/views.xml</value> </list> </property> </bean> --> </beans> applicationContext.xml <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="Index of /schema/beans" xmlns:xsi="Page on w3.org" xsi:schemaLocation="Index of /schema/beans Page on springframework.org"> <!-- Root Context: defines shared resources visible to all other web components --> <!-- CSRF protection. Here we only include the CsrfFilter instead of all of Spring Security. See Spring Security Reference for more information on Spring Security's CSRF protection --> <!-- <bean id="csrfFilter" class="org.springframework.security.web.csrf.CsrfFilter"> <constructor-arg> <bean class="org.springframework.security.web.csrf.HttpSessionCsrfTokenRepository"/> </constructor-arg> </bean> --> <!-- Provides automatic CSRF token inclusion when using Spring MVC Form tags or Thymeleaf. See Page on localhost:8080 and form.jsp for examples --> <!-- <bean id="requestDataValueProcessor" class="org.springframework.security.web.servlet.support.csrf.CsrfRequestDataValueProcessor"/> --> </beans> web.xml <web-app xmlns="Java EE: XML Schemas for Java EE Deployment Descriptors" xmlns:xsi="Page on w3.org" xsi:schemaLocation="Java EE: XML Schemas for Java EE Deployment Descriptors Page on sun.com" version="2.5"> <!-- <display-name>Spring With MongoDB Web Application</display-name> --> <servlet> <servlet-name>dispatcher</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <init-param> <param-name>contextConfigLocation</param-name> <param-value>WEB-INF/dispatcher-servlet.xml</param-value> </init-param> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>dispatcher</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> <context-param> <param-name>contextConfigLocation</param-name> <param-value>WEB-INF/dispatcher-servlet.xml</param-value> </context-param> <welcome-file-list> <welcome-file>/search.jsp</welcome-file> </welcome-file-list> </web-app> I tried several solutions given online like 1) Giving read, write permissions to all files - Doesn't work 2) Adding init-param - doesn't work 3) Explicitly giving path of dispatcherservlet as /WebContent/WEB-INF/dispatcher-servlet.xml - doesn't work. I get this error when I run the project on Apache tomcat server v7.0 I am struck with this problem for past 4 days. I have also asked this in stackoverflow and no positive response. Please help me.

• Answer:

  In your WAR file, is the dispatcher-servlet.xml in the WEB-INF folder?