How do I parse a JSON string in scala?

Hey Luke. {a:  '1'} is not valid JSON for a couple of reasons, from what I can tell: a needs to be a string ("a") and you need to use double quotes for "1". Try: scala> scala.util.parsing.json.JSON.parseFull("""{"a":1}""") res2: Option[Any] = Some(Map(a -> 1.0))

I have started hacking away using the Scala JSON toolkit https://github.com/stevej/scala-json It was originally from the Odersky "Stairway" Book, and @stevej tightened it up also using spec tests added by Twitter, Inc.

You can try with Genson, see the http://owlike.github.io/genson/Documentation/ScalaGuide/. It just works, is easy to use and fast and comes with a rich set of features. It integrates also with libraries like jodatime and json4s if you want to use its DOM API (JObject/Array etc). As you can see the code to write is really minimal (no sily implicits everywhere or whatever): // Import the default preconfigured Genson instance or provide a custom one import com.owlike.genson.defaultGenson_ val json = toJson(Person("foo", 99)) val person = fromJson[Person]("""{"name": "foo", "age": 99}""") case class Person(name: String, age: Int)

As in java I am using Jackson to marshal json to class. For that you need to register ScalaModule to your json instance in order to support Scala collections and case classes