How would I solve this equation?
-
In the equation below there are two variables x and y. How do you solve this equation for x and how do you solve for y?6x - 3 – y = 15 + 5yplease leave an explanation if you can along with the answer.
-
Answer:
Here's a similar problem: Solve for x 2x + y = -y + 4 - y. - y 2x = -2y + 4 /2 /2 x = -y + 2 Answer Now you would do it similarly for y. ------ We are not supposed to do all the work for you and give the answers.
naterod99 at Ask.com old Visit the source
Other answers
You can solve in terms of x and in terms of y. All you do is get y (no coefficients,) alone on one side with everything else on the other side. Same thing for x. ^ is right if you need an actual number answer.
pak918
You can't unless there are two equations. You can simplify for either variable though.
TheDoc
You can only find x in terms of y/y in terms of x.
doesnt_matter_to_you
Related Q & A:
- How to find the global equation of a dual curve?Best solution by Mathematics
- How can I evaluate an equation within a String?Best solution by stackoverflow.com
- How do I solve the problem of downloading word document attached to my email?Best solution by support.google.com
- How do I solve a DNS error?Best solution by Yahoo! Answers
- How do I solve the coin problem?Best solution by Quora
Just Added Q & A:
- How many active mobile subscribers are there in China?Best solution by Quora
- How to find the right vacation?Best solution by bookit.com
- How To Make Your Own Primer?Best solution by thekrazycouponlady.com
- How do you get the domain & range?Best solution by ChaCha
- How do you open pop up blockers?Best solution by Yahoo! Answers
For every problem there is a solution! Proved by Solucija.
-
Got an issue and looking for advice?
-
Ask Solucija to search every corner of the Web for help.
-
Get workable solutions and helpful tips in a moment.
Just ask Solucija about an issue you face and immediately get a list of ready solutions, answers and tips from other Internet users. We always provide the most suitable and complete answer to your question at the top, along with a few good alternatives below.