What is the preparation of normal saline solution?
If a pharmacist mixed a 10% saline solution with a 15% saline solution to obtain 80mL of a 12% saline solution, how much of the 10% saline solution did the pharmacist use?
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Answer:
10x + 15(100-x) = 12(100)10x + 1500 - 15x = 1200-5x + 300 = 0Add 5x to each side:300 = 5xdivide both sides by 5+300%2F5+=+5x%2F5+ so 60 = x
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