What is the freezing point of water?

What is the boiling point of a solution 0.150g of glycerol, c3h8o3 in 20g of water? what is the freezing point?

• I mostly dont know how to get the freezing point, I know how to get the boiling point but now I am stuck on the freezing point, I know the answer is -0.151 degrees celsius and i know ...show more

• Answer:

  (0.150 g C3H8O3) / (92.0938 g C3H8O3/mol) / (20 g) x (1000 g) = 0.081439 m (-1.86 °C/m) x (0.081439 m) = -0.151°C change 0°C -0.151°C = -0.151°C (0.512 °C/m) x (0.081439 m) = 0.0417 °C change 100°C + 0.0417 °C = 100.0417 °C