How do I calculate the partial pressure of HCl?

Q 5.00L evacuated cylinder is charged with 25.5 g NH3 and 36.5 g HCl. Calculate the final pressure at 85 degrees C after the two compounds?

  • have reacted completely.

  • Answer:

    NH3 + HCl ------> NH4Cl determine limiting reactant- moles NH3: 25.5 g NH3/17 g/mole NH3= 1.5 moles HCl: 36.5 g HCl/36.5 g/mole HCl= 1 from bal. rxn., 1 mole of NH3 reacts with 1 mole HCl, 1:1, therefore 0.5 moles of NH3 is in excess PV=nRT, where n= no. of moles and T is temp. in oK P=nRT/V substitute values and solve for P

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