A rock band plays at a(n) 70-dB sound level.?
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A rock band plays at a(n) 70-dB sound level. How many times greater is the sound pressure from another rock band playing at each of the following sound levels?
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Answer:
You didn't give the numbers but... The sound intensity is 10^(dB difference)/10 times greater. The ratio of sound pressure would be the square root of that. For instance, suppose one of the numbers was 82 dB. That is 82 - 70 = 12 dB greater. So the ratio of sound intensities is 10^(12/10) = 10^1.2 = 15.8 times higher, and the sound pressure is sqrt(15.8) = 3.98 times higher.
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