What would be the main-sequence life expectancy (years on the main sequence) of two stars?!?!?
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What would be the main-sequence life expectancy (years on the main sequence) of a 0.75 solar mass star and a 2.3 solar mass star? Show your calculations. Please or just help ...show more
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Answer:
τ(M/M๏=0.75) = 3.99e10 years τ(M/M๏=2.30) = 8.61e8 years My curvefits shown below. If M/M๏ is between 0.6 and 1.0, then L/L๏ = 10^{0.3124895 (M/M๏)² + 2.35668555 (M/M๏) − 2.66917505} If M/M๏ is between 1.0 and 2.0, then L/L๏ = (M/M๏)^4.041384 If M/M๏ is between 2.0 and 20.0, then L/L๏ = 1.505964 (M/M๏)^3.5 − 0.0252982 (M/M๏)^4.5 If M/M๏ is greater than 20.0 then L/L๏ = (M/M๏)^3.5 T๏ = 5770K If M/M๏ is less than 0.6, then BEGIN T = −128573.17631 (M/M๏)⁴ + 196041.80636 (M/M๏)³ − 103996.03306 (M/M๏)² + 24245.95618 (M/M๏) + 1012.30222 R/R๏ = −6.1108745 (M/M๏)⁴ + 13.1850512 (M/M๏)³ − 8.9344 (M/M๏)² + 3.12838735 (M/M๏) − 0.0969583 L/L๏ = (R/R๏)² (T/T๏)⁴ END If M/M๏ is greater than 0.5, then τ = (1e10 years) (M/M๏)/(L/L๏) If M/M๏ is between 0.25 and 0.5, then τ = (510.155892 years) exp{34.7792122 (M/M๏)} + (2.13956632e13 years) exp{−11.6197093 (M/M๏)} If M/M๏ is less than 0.25, then τ = (8.905387e10 years) (M/M๏)^(−1.8586791)
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