What is the freezing point depression of water in a solution of 17.1 g of CaCl2 and 200. g of water? (Kb = -1.86)?
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What is the freezing point depression of water in a solution of 17.1 g of CaCl2 and 200. g of water? (Kb = -1.86) Select one: a. -4.3oC b. 4.3oC c. 1.4oC d. -1.4oC e. 0
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Answer:
17.1 g / 110.98 g/mol = 0.154 mole -1.86x3x0.154/0.200 kg=-1.43ºC (d) -1.4ºC
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