How to Get Main output into Common() method in Java?

Doesn't the execution of a Java program start with the main() method? Why is the first output of the following program not "in main" but rather "super static block"?

• class StaticSuper { static { System.out.println(“super static block”); } StaticSuper() { System.out.println(“super constructor”); } } public class StaticTests extends StaticSuper { static int rand; static { rand = (int) (Math.random() * 6); System.out.println(“static block “ + rand); } StaticTests() { System.out.println(“constructor”); } public static void main(String [] args) { System.out.println(“in main”); StaticTests st = new StaticTests(); } } The output is: super static block static block 3 in main super constructor constructor Where does execution start? If it is from the main() method, why isn't in main the first output? Am assuming it gets printed before StaticTests constructor gets invoked. This constructor in turn calls the constructor in StaticSuper. At this point, the static initializer in StatiSuper get executed then the object is created. Execution then goes back to the constructor in StaticTests, etc... I know that a static initializer runs before a constructor. But if the whole program execution is starting from the main() method, shouldn't "in main" be printed first?

• Answer:

  Class static code is executed when the class is loaded by the class loader. The class has to be loaded before its main can even be found. It's confusing, that's why class static code is to be avoided.