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What is intermediate algebra?

Intermediate Algebra problems help?

  • Hello, I'm in need of major help on some equations.. I have an exam coming up for finals and I'm horrid at algebra in general. I'm in intermediate algebra for the second ...show more

  • Answer:

    For questions 1 and 2 you need to use brackets to make clear what is included under the radical sign 3. 35x = 5*7*x 5x^2 = 5*x*x 7x^3 = 7*x*x*x Now take the highest power of each factor and multiply them together The highest power for x is 3, highest power of 5 is 1 and highest power of 7 is 1, so LCM = 5*7*x^3 = 35x^3 4. 3x/10x - 9/14x^2 = [(3x)(14x^2) - (10x)(9)]/[(10x)(14x^2] = [42x^3 - 90x]/[140x^3] = [3x(14x^2 - 30)]/[140x^3] = [6x(7x^2 - 15)]/[140x^3] = (3/70)[7x^2 - 15]/x^2 5 12m^2p^2/4m^10p = (12/4)(m^2/m^10)(p^2/p) = (3)(1/m^8)(p) = 3p/m^8 6 3x^2/5 / x^3/30 = (3x^2/5)*(30/x^3) = (90/5)*(x^2/x^3) = 18/x 7 All real numbers, except x = - 3/4 If you are happy with what I have done so far you can send the other questions to [email protected]

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√4q + 5 = 5 2q + 5 = 5 2q = 0 q = 0 I suspect you're missing parentheses throughout. Perhaps you meant √(4q + 5) = 5 4q + 5 = 25 4q = 20 q = 5 One question at a time.

Iggy Rocko

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