How many liters of hydrogen sulfide may be produced from 264 grams of ferrous sulfide?

CHEM HELP! If we start out with 1.4 grams of magnesium and 8.1 grams of sulfuric acid, How many grams of hydrogen can be produced?

• magnesium reacts with sulfuric acid to produced magnesium sulfate and hydrogen. Mg (s) + H2SO4 (aq) ---> MgSO4 (aq) + H2 If we start out with 1.4 grams of magnesium and 8.1 ...show more

• Answer:

  A.) (1.4 g Mg) / (24.30506 g Mg/mol) = 0.05760 mol Mg (8.1 g H2SO4) / (98.0791 g H2SO4/mol) = 0.08259 mol H2SO4 0.05760 mole of Mg would react completely with 0.05760 mole of H2SO4, but there is more H2SO4 present than that, so H2SO4 is in excess and Mg is the limiting reactant. (0.05760 mol Mg) x (1 mol H2 / 1 mol Mg) x (2.015894 g H2/mol) = 0.12 g H2 in theory B. (0.0600 g) / (0.12 g) = 0.50 = 50% yield C. ((0.08259 mol H2SO4 initially) - (0.05760 mol H2SO4 reacted)) x (98.0791 g H2SO4/mol) = 2.5 g H2SO4 left over