[Discrete Mathematics] How to prove a function is big-theta(n^3/2)?
-
The function I was given is (n+1)3/2. I understand that I have to prove that it is both big-O(n3/2) and big-Omega(n3/2). I know how to do this for polynomial functions such as n2 and ...show more
-
Answer:
Upper bound. For all n > 1: (n+1)^(3/2) < (n+n)^(3/2) = 2^(3/2) * n^(3/2). Lower bound. For all n > 0: (n+1)^(3/2) > (n+0)^(3/2) = n^(3/2). All together, we have 1 * n^(3/2) < (n+1)^(3/2) < 2^(3/2) * n^(3/2) for all n > 1. Hence, (n+1)^(3/2) is Θ(n^(3/2)). I hope this helps!
JK54GL7XXY2Z26X4URCSVXVZFY at Yahoo! Answers Visit the source
Related Q & A:
- How to call a function with parameter in a bash script?Best solution by tldp.org
- How to fire a function before and after automatically in a jquery plugin?Best solution by catchmyfame.com
- how to call a function in Python in another function?Best solution by Yahoo! Answers
- How to create a build system in Sublime Text 3?Best solution by stackoverflow.com
- How to call a function asynchronously in PHP?Best solution by Stack Overflow
Just Added Q & A:
- How many active mobile subscribers are there in China?Best solution by Quora
- How to find the right vacation?Best solution by bookit.com
- How To Make Your Own Primer?Best solution by thekrazycouponlady.com
- How do you get the domain & range?Best solution by ChaCha
- How do you open pop up blockers?Best solution by Yahoo! Answers
For every problem there is a solution! Proved by Solucija.
-
Got an issue and looking for advice?
-
Ask Solucija to search every corner of the Web for help.
-
Get workable solutions and helpful tips in a moment.
Just ask Solucija about an issue you face and immediately get a list of ready solutions, answers and tips from other Internet users. We always provide the most suitable and complete answer to your question at the top, along with a few good alternatives below.