What is the blades rotational kinetic energy and what average power is needed?
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A 21cm-diameter circular saw blade has a mass of 0.89kg, distributed uniformly as in a disk. a)What is its rotational kinetic energy at 3500rpm? b)What average power must be ...show more
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Answer:
a) KEr = 1/2 Iw^2 = 1/2 kmr^2 w^2 = 1/4*.89*.21^2*(2*pi()*3500/60)^2 = 1.3181E+03 Joules ANS. b) P = KEr/T = 1.32E3/2.5 = 5.2800E+02 = 528 Watts. ANS.
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