Solve the system, using substitution. Write the solution as an ordered pair. x = 2y - 2 and 3x - y = 14 no solution, (0,1) (6,4) (4,6)?
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Solve the system, using substitution. Write the solution as an ordered pair. x = 2y - 2 and 3x - y = 14 no solution (0, 1) (6, 4) (4, 6) (1, 0)
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Answer:
x = 2y - 2 3x - y = 14 substitute first equation into second equation: 3(2y - 2) - y = 14 distribute: 6y - 6 - y = 14 combine like terms: 5y = 20 divide: y = 20/5 = 4 using first equation: x = 2(4) - 2 = 6 check using second equation: 3(6) - (4) = 14 checks solution set (6, 4) - second choice - .--
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