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What is the electron dot structure?

How to find the amount of electron pairs using the lewis dot structure?

  • Gallium has 3 valence electrons. By using the lewis dot structure, is there a simple way to find how many pairs of electrons are in an element. Thank you guys so much!!

  • Answer:

    Total pairs as in 1s2, 2p6, etc...? No. You'd have to know which noble gas precedes the element. In this case, Argon (18) Ga would be [Ar] 4s2, 3d10, 4p1 Pairs in the valence shell, yes. Since it has 3 electrons in the valence shell Hund's Rule states the 3 electrons will fill 4s2, 4px 1, 4py 0, and 4pz 0. Oxygen would be [He] 2s2, 2px2, 2py1, 2pz1.

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The answer is yes, but only if you follow the rules for writing LDS's for elements (and the rules are only good for the representative elements anyhow). Write the element symbol, then put in the number of dots equal to the valence electrons (once upon a time, that was the family number). The first dot goes on any side (one unpaired electron), the next dot goes next to it (one electron pair in the s orbital). The next dot goes on another side, the next on a different side and the next on the remaining side (unpaired electrons in the p orbitals). The next electrons pair up in those p orbitals. Ga would be :Ga.

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