What mass in grams of hydrogen gas is produced if 75.0 mol of Zn...?
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What mass in grams of hydrogen gas is produced if 75.0 mol of Zn are added to excess hydrochloric acid according to the equation: Zn(s) + 2HCl(aq)-->ZnCl2(aq)+ H2(g)? (ZnCl2= ...show more
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Answer:
the key word is "excess." we don't care how much HCl is added since it's not the limiting reagent. we know that 75.0 moles of Zn are added to the reaction, so therefore 75.0 moles of ZnCl2 will be formed (since they are in a 1 to 1 ratio). Since 2 Cl atoms are used in that molecule, and hydrogen gas uses 2 hydrogen atoms, we can just come to the conclusion that 75.0 moles of hydrogen gas was formed since the reagents are proportionally equal. 136.28 * 75 moles = 10221 g
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