How do you find the graph of a circle using the center (h,k) and radius r if a circle has the equation x^2+y^2+2x-2y-34=0?
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How do you find the graph of a circle using the center (h,k) and radius r if a circle has the equation x^2+y^2+2x-2y-34=0
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Answer:
x^2 + 2x + y^2 - 2y = 34 complete the squares for x and y ___ x^2 + 2x + 1 + y^2 - 2y + 1 = 34 + 1 + 1 (x + 1)^2 + (y - 1)^2 = 6^2
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