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What is the fare for Canada Line?

In 2001, bus fare on the line was $3.60. In 1975, the fare was 5/8 the fare in 2001.What was the fare in 1975.?

  • need to slove a math problem franction

  • Answer:

    Wonderful. Multiply $3.60 multiplied by the Engine displacement of the Bus in which you traveled, and divide it by the number of seats in the bus. You get a figure. Then you multiply this by 5 and divide by 8, and then add the Engine displacement of the bus in 1975, plus the weight of the driver. This result should be multiplied by the diameter of the front two tires, plus add the air pressure in all the four tires. And finally check the wheel clearance of the bus, and use that figure to multiply once again. You shall get the actual figure you are looking for.

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How does a bus fare math problem relate to VW cars?

djaca70

I won't do your work but I will tell YOU how to do it. To multiply by a fraction you multiply the number by the numerator and divide the result by the denominator. Now if you don't understand those terms then you weren't paying attention in class. ADDED: If you believe Ralph you're in big trouble. Prices that are a fraction of another can't be larger than the original.

mustanger

divide 3.60 by 8 than times that answer by 5 this will be the fare for 75

KAM

okay so the fare in 75 is the unknown or x =( 3.60 x 5) / 8, which gives 18.00 / 8 which is $2.25 you can check you work by seeing if 2.25 / 3.60 is = 5 / 8 too by 2.25 x 8 / 3.60 = 5, gives 18.00 / 3.60 = 5 and yes it is. Basically to start it is Fare in 75 / Fare in 01 = 5 / 8 then plug and chug, you know Fare in 01

Pure Fun

The price was $5.76

Ralph

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