Does changing the mass or volume of water change its density?

Does changing the mass or volume of water change its density?

• please explain why or why not?

• Answer:

  You did not explain the question enough: are we talking about pure water-in constant conditions, or unpure water? The density will not change, even if the water is not pure; or you are only increasing the mass or volume of water (which is impossible). Answer: The density will not change. Explanation: Changing the mass of the water (pure water): Increasing the mass of water would result in increasing the density, BUT since you are increasing the mass, the volume will increase as well, unless in a specific situation, which is impossible. Answer: No, the density will not change.. Decreasing the mass of water would result in decreasing the density, BUT since you are decreasing the mass, the volume will decrease as well, unless again, in a specific situation, which is impossible. Changing the volume of the water (pure water): Increasing the volume of water would result in decreasing the density, BUT since you are increasing to volume, the mass will increase as well, unless, in a very specific condition, which is impossible. Decreasing the volume of water would result in increasing the density BUT since you are decreasing the volume, the mass will decrease as well, unless again, in a specific condition, which is impossible. Changing the mass/volume of the water (unpure water): The same rules will apply even if the water is unpure;the density will be different from pure water though, because this water has another substance's density in it. Examples: (*Please note that D=Density, W=Water, M=Mass, V=Volume*) D of W = M/V M/V=D of W. If we have 100 grams of water, we WILL have 100 milliliters of water. Therefore, 100/100=1. D=1m/v. M: V*(times)D. We have V and D, but not M. Find M--- V*(times)D=M. If we have 100 liters of water. The density is 1. 100 times 1 = 100. M=100kg. V: M*(times)D. We have M and D, but not M. Find M. If we have 400 grams of water, 400 times 1=400. V=400mL. Same for unwater. For example, if we have two substances mixed: Mercury and water. If we have V and M of both mercury and water, we can find the density of the mixed subtance. For example: V is 100 mL and M is 1390 g of MERCURY, and V is 2000 mL and M is 2000 g of WATER: We will add the V and M of both substances and divide the TOTAL: 100+2000 divided by 1390+2000 =2100 divided by 3390 =M/V. But since 2100 is the volume, we must divde 3390 by 2100 =3390 divided by 2100 =1.61 (rounded) =The D [density] of the mixed substance, mercury and water is 1.61 g/mL. Thanks, hope I helped! Cheers!