What substance has a specific heat that is higher than liquid water?

If 50 grams of a substance with a temp of 20 degree Celsius and specific heat of 2 is mixed with 200 grams of water with a temperature of 40 degree Celsius what will be the equilibrium temperature of?

• Answer:

  Heat gained by one object has to equal the heat lost by the other object. The final temperature of the two objects will be the same. Object 1: mass1 = 50 g initial T1 = 20 oC Cg = 2 J/degree/gram final T1 = Tf Change in temperature = Tf - T1 Q = Cg x change in T x mass = 2 x ( Tf - T1 ) x 50 Water: Mass = 200 g Cg = 4.18 J/ degree/ gram Change in T = Tf - 40 Q = 4.18 x (Tf - 40) x 200 4.18 x (Tf - 40) x 200 = -(2 x ( Tf - 20 ) x 50) Tf = 37.9 oC