What is the theoretical yield of grams of alum, or KAl(SO4)2?
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Answer:
Before performing chemical reactions, it is helpful to know how much product will be produced with given quantities of reactants. This is known as the theoretical yield. For KAl(SO4)2, (5 g Al)*(1 mol Al/26.982 g Al)* (1 mol KAl(SO4)2·12(H2O))/ 1 mol Al)*(258.21 g KAl(SO4)2·12(H2O))/ 1 mol KAl(SO4)2·12(H2O)) = 5/26.982*258.21 = 47.849 grams alum.
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