How to style PHP output?

Drupal (CMS): How do I write PHP to output the path an image from a CCK imagefield?

• Here is my specific situation: My nodes have a CCK imagefield. Hence, each node will have a different image uploaded. I would like to 'raw' output that URL path of the image using PHP. I need this path for Facebook's OpenGraph meta tags (http://developers.facebook.com/docs/opengraph/). For example: <meta property="og:image" content="<?php OUTPUT IMAGE PATH HERE ?>"/>

• Answer:

  To get the path of the image [AND the facebook markup] to show on the NODE page do the following: Modules needed:      viewfield  views 1] Create a new view and name it Facebook-Meta [only a default will be created. NO block or Page etc]]         Set an argument for NID that is set to default to the NID from the URL.         Add a field for the image and set the display format to IMAGE PATH & rewrite the output of the field. In the text field provided enter the Facebook markup and use the TOKEN provided that plugs the image path into the rewrite text. 2] Go to the MANAGE FIELDS of your content type and add a new field labeled Facebook-Meta and select the VIEWFIELD as its type. From the list provided choose the Facebook-Meta view from the list towards the bottom. In the ARGUMENT field at the bottom add these 4 characters  %nid That should do it. You may need to tweek the textfield of the REWRITE output to get facebook totally happy with your syntax. Let me know how this goes for you! :-) - Doug Vann [Drupal Trainer , Consultant , Developer] - http://dougvann.com